2x^2-x-496=0

Solution for 2x^2-x-496=0 equation:

2x^2-x-496=0

We add all the numbers together, and all the variables

2x^2-1x-496=0

a = 2; b = -1; c = -496;
Δ = b2-4ac
Δ = -12-4·2·(-496)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-63}{2*2}=\frac{-62}{4}
=-15+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+63}{2*2}=\frac{64}{4}
=16
$